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Modern Physics

Nuclear Fusion

Nuclear fusion is a nuclear reaction in which two or more atomic nuclei collide at very high speeds and combine to form a new type of atomic nucleus, releasing enormous amounts of energy. This process powers active stars and thermonuclear weapons.

UP TGT ScienceUP PGT PhysicsStudy Notes + Practice

Scope and prerequisites

TGT core

Definition of nuclear fusion, basic understanding of mass defect, energy release in proton-proton chain and carbon-nitrogen cycle, comparison with nuclear fission, and conditions required for fusion (high temperature and pressure).

PGT extension

Detailed reaction cross-sections, Coulomb barrier penetration probability via quantum tunneling, Gamow peak derivation, Lawson criterion for controlled thermonuclear fusion, and magnetic/inertial confinement concepts.

Prerequisites

  • Mass-energy equivalence (Einstein's relation E = mc<sup>2</sup>)
  • Binding energy per nucleon curve and nuclear stability
  • Coulomb electrostatic repulsion between charged nuclei

Fundamental Mechanism of Nuclear Fusion

  • Light nuclei are brought within the range of the strong nuclear force (approx. 1 to 3 fm), overcoming their mutual electrostatic Coulomb repulsion.
  • The total rest mass of the product nuclei is less than the total rest mass of the reactant nuclei, yielding a positive mass defect (Δm).
  • The missing mass is converted directly into energy according to $E = (Δm)c^{2}$, which appears as kinetic energy of the reaction products and gamma radiation.

Stellar Fusion Cycles

  • In stars like the Sun, the primary energy source is the proton-proton (p-p) chain, converting four protons into one 4He nucleus and two positrons, with a net energy release of about 26.7 MeV.
  • In heavier and hotter stars (T > 1.5 × 107 K), the Carbon-Nitrogen-Oxygen (CNO) cycle acts as a catalytic pathway for hydrogen fusion.
  • Deuterium-Tritium (D-T) fusion has the lowest ignition temperature and highest cross-section, making it the primary reaction studied for terrestrial controlled fusion reactors.

The Coulomb Barrier and Quantum Tunneling

  • Two positively charged nuclei experience a strong Coulomb repulsive potential barrier Vc = (1 / 4πε0) (q1q2 / r), which is typically on the order of hundreds of kiloelectronvolts (keV).
  • Thermal energies in stellar cores (kT ~ 1 keV) are far lower than the classical Coulomb barrier height, meaning particles lack classical turning points to touch.
  • Fusion proceeds due to quantum mechanical wave-particle duality, allowing particles to tunnel through the Coulomb potential barrier with a finite transmission probability.

Lawson Criterion for Controlled Fusion

  • The Lawson criterion specifies the minimum product of plasma density (n), confinement time (τE), and plasma temperature (T) required for a fusion reactor to achieve ignition.
  • Ignition occurs when the power generated by alpha particles produced in fusion reactions equals or exceeds the total radiation and conduction losses.
  • For a D-T plasma, the required temperature is approximately 1 to 2 × 108 K (or 10 to 20 keV).

Derivations

Energy Release (Q-value) in Deuterium-Tritium Fusion

Conditions: Reaction: 2H + 3H → 4He + n

  • Write the mass balance equation using atomic mass units (u): m(2H) + m(3H) = m(4He) + m(n).
  • Substitute atomic masses: m(2H) = 2.014102 u, m(3H) = 3.016049 u, m(4He) = 4.001506 u, m(n) = 1.008665 u.
  • Calculate total initial mass: Mi = 2.014102 + 3.016049 = 5.030151 u.
  • Calculate total final mass: Mf = 4.001506 + 1.008665 = 5.010171 u.
  • Determine mass defect Δ$m = M_{i} - M_{f} = 5.030151 u - 5.010171 u = 0.019980 u$.
  • Convert mass defect to energy using 1 $u = 931.5 MeV/c^{2}$.

Result: $Q = 0.019980 u \times 931.5 MeV/u ≈ 17.6 MeV$

Gamow Peak Derivation Context for Reaction Rate

Conditions: Maxwell-Boltzmann thermal distribution combined with quantum tunneling probability (Gamow factor)

  • The Maxwell-Boltzmann velocity distribution gives the relative number of particles with kinetic energy E as proportional to exp(-E / kT).
  • The quantum mechanical transmission coefficient (Gamow factor) for two nuclei with charges Z1e and Z2e is proportional to exp(-b / sqrt(E)), where b is the Gamow constant.
  • The total reaction rate is proportional to the product of these two competing functions: P(E) ∼ exp(-E / kT - b / sqrt(E)).
  • Differentiate the exponent with respect to E and set to zero to find the most probable energy (Gamow peak energy E0) at which nuclear reactions occur.

Result: $E_0 = \left( \frac{b k T}{2} \right)^{2/3}$

Formula sheet

Formula / lawEquationVariables and unitsConditions
Mass-Energy Equivalence$$E = \Delta m c^{2}$$E = Energy released, Δm = Mass defect, c = Speed of light in vacuum
E in Joules (J) or MeV, Δm in kg or u
Applies to all nuclear reactions
Coulomb Potential Energy Barrier$$V_{c} = \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r}$$Vc = Potential energy, q1, q2 = Charges of interacting nuclei, r = Separation distance
Joules (J) or eV
Valid at classical closest approach distance
Q-Value of a Nuclear Reaction$$Q = \left( \sum M_{\text{reactants}} - \sum M_{\text{products}} \right) c^{2}$$M = Rest masses of nuclei
MeV
Positive Q indicates exothermic reaction
Gamow Penetration Factor Exponent$$G = \pi \alpha Z_{1} Z_{2} \left( \frac{2 \mu c^{2}}{E} \right)^{1/2}$$α = Fine-structure constant, μ = Reduced mass, E = Center of mass kinetic energy
Dimensionless
Low-energy non-relativistic approximation
Gamow Peak Energy$$E_{0} = \left( \frac{b}{2} k T \right)^{2/3}$$E0 = Most effective energy for fusion, b = Gamow constant, k = Boltzmann constant, T = Temperature
Joules or eV
Valid for thermal Maxwellian plasma
Lawson Criterion for D-T Fusion$$n \tau_{E} \ge 10^{20} \text{ m}^{-3} \text{ s}$$n = Plasma particle density, τE = Energy confinement time
m-3s
At optimum temperature T ~ 15 keV
Proton-Proton Chain Net Energy$$4p arrow {}^{4}\text{He} + 2e^{+} + 2\nu_{e} + 26.7 \text{ MeV}$$p = proton, e+ = positron, νe = electron neutrino
MeV
Core temperature T < 1.5 × 107 K
Deuterium-Tritium Fusion Reaction$${}^{2}_{1}\text{H} + {}^{3}_{1}\text{H} arrow {}^{4}_{2}\text{He} (3.5 \text{ MeV}) + n (14.1 \text{ MeV})$$Products share 17.6 MeV total energy
MeV
Terrestrial magnetic confinement systems

Graphs and experiments

Binding Energy per Nucleon vs Mass Number Curve

Draw: A plot of binding energy per nucleon (B.E./A) in MeV on the y-axis against mass number (A) on the x-axis, showing a sharp rise for light nuclei, a peak near A = 56 (Iron), and a slow decline for heavy nuclei.

Interpret: Light nuclei (such as hydrogen, deuterium, helium) have low binding energy per nucleon. When they fuse to form heavier nuclei up to iron, the binding energy per nucleon increases, releasing the difference as binding energy.

Exam use: Directly tested in TGT/PGT to explain why fusion is exothermic for light nuclei and fission is exothermic for heavy nuclei.

Fusion Reaction Cross-Section vs Energy

Draw: A log-linear plot of nuclear fusion cross-section (σ) in barns versus center-of-mass energy (E) in keV, showing a steep rise from threshold and a distinct resonance peak (e.g., around 100 keV for D-T reaction) followed by a gradual decrease.

Interpret: At very low energies, the Coulomb barrier suppresses the cross-section. As energy increases, quantum tunneling probability rises exponentially until thermal motion and nuclear cross-section peak.

Exam use: Tested in PGT to explain optimal operating temperatures for thermonuclear reactors.

Maxwell-Boltzmann and Gamow Window Overlap

Draw: Two overlapping curves on an energy axis: a Maxwell-Boltzmann thermal distribution curve shifting downward with energy, and a steeply rising quantum penetration probability curve, whose product forms a distinct bell-shaped Gamow peak.

Interpret: Demonstrates that fusion does not happen at the highest thermal energies or at zero energy, but within a narrow energy band (the Gamow window).

Exam use: Asked in PGT conceptual questions regarding stellar nucleosynthesis rates.

Solved numericals

TGT core

Calculate the energy released in the fusion of two deuterium nuclei to form a helium-3 nucleus and a neutron: 2H + 2H → 3He + n. Given masses: m(2H) = 2.014102 u, m(3He) = 3.016029 u, m(n) = 1.008665 u. (Take 1 u = 931.5 MeV)

  • Find total mass of reactants: Mi = 2 × 2.014102 u = 4.028204 u.
  • Find total mass of products: Mf = 3.016029 u + 1.008665 u = 4.024694 u.
  • Calculate mass defect Δ$m = M_{i} - M_{f} = 4.028204 u - 4.024694 u = 0.003510 u$.
  • Calculate energy released $Q = 0.003510 u \times 931.5 MeV/u$.

Answer: 3.27 MeV

PGT extension

Estimate the height of the Coulomb potential barrier (in MeV) between two protons when their centers are separated by a distance equal to the sum of their nuclear radii, assuming $R = 1.2 \times 10^{-15} A^{1/3} m with A = 1$ for a proton.

  • Determine the closest separation distance $r = 2R = 2 \times 1.2 \times 10^{-15} m = 2.4 \times 10^{-15} m$.
  • Write Coulomb barrier formula: Vc = (1 / 4πε0) × (e2 / r).
  • Substitute constants: (1 / 4πε0) = 8.99 × 109 N m2 C-2, $e = 1.6 \times 10^{-19} C$.
  • Calculate Vc in Joules: Vc = (8.99 × 109 × (1.6 × 10-19)2) / (2.4 × 10-15).
  • Vc = (8.99 × 109 × 2.56 × 10-38) / (2.4 × 10-15) = 9.589 × 10-14 J.
  • Convert to MeV by dividing by 1.6 × 10-13 J/MeV.

Answer: 0.6 MeV

PGT extension

A thermonuclear reactor operates on D-T fusion releasing 17.6 MeV per reaction. If the reactor generates a thermal power of 500 MW, find the number of deuterium nuclei consumed per second.

  • Power $P = 500 MW = 500 \times 10^{6} J/s$.
  • Energy per reaction in Joules: $E = 17.6 MeV = 17.6 \times 10^{6} \times 1.6 \times 10^{-19} J = 2.816 \times 10^{-12} J$.
  • Number of reactions per second $n = P / E = (500 \times 10^{6}) / (2.816 \times 10^{-12})$.
  • $n = 1.775 \times 10^{19} reactions per second$.
  • Since each D-T reaction consumes exactly one deuterium nucleus, the rate of deuterium consumption equals n.

Answer: 1.78 × 1019 nuclei/s

Assumptions and limitations

  • Assumption: Maxwell-Boltzmann velocity distribution holds true for core stellar plasmas; limitation: high-energy tails can deviate in non-equilibrium plasmas.
  • Assumption: Quantum tunneling can be modeled using static Coulomb potentials; limitation: screening effects from surrounding electrons alter the effective barrier in dense laboratory plasmas.

Common misconceptions

Common error: Nuclear fusion only releases energy for hydrogen isotopes.

Correct: Fusion is exothermic for any light nuclei up to iron (A = 56). Beyond iron, fusion absorbs energy.

The binding energy per nucleon curve peaks at iron; combining nuclei lighter than iron increases binding energy and releases excess mass energy.

Common error: Particles in a star collide with sufficient thermal energy to overcome the Coulomb barrier classically.

Correct: Thermal energies in stellar cores are ~1 keV, whereas the Coulomb barrier is ~1 MeV.

Fusion occurs primarily due to quantum mechanical tunneling through the potential barrier at energies well below the classical threshold.

Quick revision

  • Nuclear fusion combines light nuclei to form heavier nuclei, releasing energy due to mass defect.
  • The proton-proton chain powers standard stars, while the CNO cycle operates in massive stars.
  • Quantum tunneling is essential for fusion because thermal energies are much lower than Coulomb barrier heights.
  • D-T fusion yields 17.6 MeV and has the lowest ignition threshold for terrestrial reactors.
  • The Lawson criterion sets the required density, temperature, and confinement time for sustained fusion energy.

Must remember

  • Nuclear fusion involves light nuclei combining to form heavier nuclei, yielding a positive mass defect and releasing energy according to $E = \Delta m c^2$.
  • The primary energy source in the Sun is the proton-proton (p-p) chain, releasing approximately $26.7\text{ MeV}$ per complete cycle.
  • Deuterium-Tritium (D-T) fusion has the lowest ignition temperature and highest cross-section, making it optimal for terrestrial controlled fusion.
  • Quantum tunneling is essential for fusion because classical thermal energies ($\sim 1\text{ keV}$) are vastly lower than the Coulomb potential barrier ($\sim 100\text{ keV}$ to $\text{MeV}$).
  • The Lawson criterion specifies the threshold condition of plasma density ($n$), confinement time ($\tau_E$), and temperature ($T$) required for ignition.

Glossary

Mass Defect ($\Delta m$)The difference between the total rest mass of individual nucleons and the rest mass of the bound nucleus.
Coulomb BarrierThe electrostatic repulsive potential barrier between two positively charged nuclei that must be overcome for them to interact via the strong nuclear force.
Quantum TunnelingThe quantum mechanical phenomenon where a particle penetrates a potential energy barrier higher than its kinetic energy.
Lawson CriterionA figure of merit used in nuclear fusion research that defines the minimum $n \tau_E T$ product required for a self-sustaining fusion reaction.
Gamow PeakThe narrow energy window in a thermal plasma where the product of the Maxwell-Boltzmann distribution and the quantum tunneling probability is maximized.

Proton-Proton Chain vs CNO Cycle

FeatureProton-Proton (p-p) ChainCNO Cycle
Primary Stellar TypeStars like the Sun ($T < 1.5 \times 10^7\text{ K}$)Heavier and hotter stars ($T > 1.5 \times 10^7\text{ K}$)
CatalystsNone (direct proton fusion)Carbon, Nitrogen, and Oxygen nuclei
Temperature DependenceWeaker temperature dependenceStronger temperature dependence

Nuclear Fission vs Nuclear Fusion

FeatureNuclear FissionNuclear Fusion
Reaction TypeSplitting of a heavy nucleus into lighter fragmentsCombining of light nuclei into a heavier nucleus
Fuel SourceHeavy elements like Uranium ($^{235}\text{U}$)Light isotopes like Hydrogen ($^2\text{H}$, $^3\text{H}$)]
Binding Energy per NucleonIncreases as fragments are formedIncreases as lighter nuclei combine up to iron

Practice Quiz

Choose an option to reveal the explanation.

1. What is the primary mechanism that enables light nuclei to overcome electrostatic repulsion during fusion at stellar core temperatures?

Explanation: Because stellar thermal energies ($\sim 1\text{ keV}$) are much smaller than the Coulomb barrier height ($\sim 100\text{ keV}$ to $\text{MeV}$), particles lack sufficient classical energy. Fusion proceeds via quantum mechanical tunneling through the potential barrier.

2. How much net energy is released in the standard proton-proton (p-p) chain converting four protons into one $^{4}\text{He}$ nucleus?

Explanation: The p-p chain converts four protons into a $^{4}\text{He}$ nucleus along with two positrons and electron neutrinos, resulting in a net energy release of about $26.7\text{ MeV}$.

3. Which fusion reaction is currently preferred for terrestrial controlled fusion reactors due to its relatively low ignition temperature and high reaction cross-section?

Explanation: Deuterium-Tritium (D-T) fusion has the largest reaction cross-section at lower temperatures compared to other light-nucleus combinations, making it the primary focus for magnetic and inertial confinement.

4. What does the Lawson criterion primarily evaluate in controlled fusion research?

Explanation: The Lawson criterion specifies the minimum required product of plasma density ($n$), energy confinement time ($\tau_E$), and temperature ($T$) so that fusion heating balances radiation and conduction losses.

5. What is the role of the strong nuclear force in nuclear fusion?

Explanation: The strong nuclear force is attractive and has a very short range ($\sim 1-3\text{ fm}$). Once electrostatic repulsion is overcome and nuclei get within this range, the strong force binds them together.

6. In the Deuterium-Tritium fusion reaction ${}^{2}_{1}\text{H} + {}^{3}_{1}\text{H} arrow {}^{4}_{2}\text{He} + n$, what is the kinetic energy carried away by the neutron?

Explanation: The total energy released in D-T fusion is $17.6\text{ MeV}$, which is shared between the $\alpha$ particle ($3.5\text{ MeV}$) and the neutron ($14.1\text{ MeV}$) via momentum conservation.

7. What is the physical significance of the Gamow peak in stellar nuclear fusion?

Explanation: The Gamow peak is the optimum energy window where fusion reactions are most probable in a thermal plasma, balancing declining particle velocity distributions against rising tunneling probabilities.

8. Why does nuclear fusion cease to be exothermic for nuclei heavier than iron ($A = 56$)?

Explanation: The binding energy per nucleon peaks around iron ($A = 56$). For elements heavier than iron, combining nuclei results in products with lower binding energy per nucleon, making fusion endothermic.

9. Which stellar fusion cycle becomes dominant in stars with core temperatures exceeding $1.5 \times 10^7\text{ K}$?

Explanation: At higher core temperatures ($T > 1.5 \times 10^7\text{ K}$), the CNO cycle has a steeper temperature dependence than the p-p chain and becomes the dominant hydrogen-burning pathway.

10. What is the general expression for the Coulomb potential energy barrier $V_c$ between two interacting nuclei with charges $q_1$ and $q_2$ separated by distance $r$?

Explanation: The classical electrostatic potential energy between two point charges is given by $V_c = \frac{1}{4\pi\varepsilon_0} \frac{q_1 q_2}{r}$.

11. What is the condition for a nuclear reaction to be exothermic based on the Q-value?

Explanation: A positive Q-value ($Q > 0$) indicates that the total rest mass of reactants exceeds that of products, resulting in a release of kinetic energy (exothermic reaction).

12. What is the approximate temperature range required for a D-T fusion plasma to satisfy the Lawson ignition criterion?

Explanation: For D-T fusion, the optimal plasma temperature for ignition is around $1$ to $2 \times 10^8\text{ K}$ (equivalent to $10$ to $20\text{ keV}$).

13. Which of the following particles are produced alongside $^4\text{He}$ in the basic proton-proton chain step producing helium-4?

Explanation: The net p-p chain converts four protons into one $^{4}\text{He}$ nucleus, accompanied by two positrons ($e^+$) and two electron neutrinos ($\nu_e$).

14. How does the Gamow penetration factor exponent $G$ scale with the relative center-of-mass kinetic energy $E$ of fusing particles?

Explanation: The Gamow exponent contains the term $\left(\frac{2\mu c^2}{E}\text{ }\right)^{1/2}$, meaning $G$ is proportional to $E^{-1/2}$. Lower kinetic energies result in larger Gamow exponents and lower tunneling probabilities.

15. In controlled nuclear fusion devices, what primary purpose do magnetic fields serve in magnetic confinement fusion (MCF)?

Explanation: Magnetic confinement uses strong magnetic fields (such as in tokamaks) to trap charged plasma particles along magnetic field lines, preventing them from touching and cooling against the reactor walls.

PYQ Patterns

These are pattern-based practice questions. Authentic year labels are only used when verified from a source.

1. If the mass defect in a nuclear fusion reaction is $\Delta m = 0.0188\text{ u}$, what is the approximate energy released? (Take $1\text{ u} \approx 931.5\text{ MeV}$)

Explanation: Using mass-energy equivalence with $1\text{ u} \equiv 931.5\text{ MeV}$, the energy released is $E = 0.0188\text{ u} \times 931.5\text{ MeV/u} \approx 17.51\text{ MeV}$, which corresponds closely to the D-T fusion energy yield.

2. Which of the following conditions is most critical for achieving controlled thermonuclear fusion in a laboratory plasma?

Explanation: As defined by the Lawson criterion, successful thermonuclear fusion requires a combination of high temperature, high particle density $n$, and long energy confinement time $\tau_E$.

3. In the proton-proton chain in stars, the first step involves two protons combining to form a deuteron, a positron, and a neutrino. Which force mediates the conversion of a proton into a neutron in this process?

Explanation: The conversion of a proton into a neutron (emitting a positron and a neutrino via $\beta$-plus decay) is governed strictly by the weak nuclear force.

4. Why is the average binding energy per nucleon higher for $^{4}\text{He}$ than for $^{2}\text{H}$?

Explanation: As light nuclei fuse into heavier ones like $^{4}\text{He}$, the binding energy per nucleon increases, signifying a more stable configuration and greater mass defect per nucleon.

5. What is the primary reason why terrestrial fusion reactors utilize Deuterium and Tritium instead of standard Hydrogen ($^1\text{H}$)?

Explanation: The cross-section for proton-proton fusion is extremely small (governed by weak interaction rates), making it unviable for terrestrial reactors. D-T fusion relies on the strong force directly, giving a much higher cross-section.

6. If a fusion reactor operates such that the fusion power generated by $\alpha$ particles exactly equals the total plasma radiation and conduction losses, the plasma is said to have achieved:

Explanation: Ignition is defined as the point where $\alpha$ particle heating alone sustains the plasma temperature without needing external heating, balancing all energy losses.

Timed Topic Test

Attempt these questions under a ten-minute limit using a separate timer.

1. What fraction of the total energy released in the Deuterium-Tritium reaction is imparted to the $\alpha$ particle?

Explanation: In D-T fusion ($17.6\text{ MeV}$ total), the $^{4}\text{He}$ nucleus receives $3.5\text{ MeV}$ and the neutron receives $14.1\text{ MeV}$, meaning the $\alpha$ particle gets about $20\%$ of the energy.

2. How does an increase in plasma temperature $T$ affect the Gamow peak energy $E_0$ in a Maxwellian plasma?

Explanation: The Gamow peak energy formula $E_0 = \left(\frac{b}{2}kT\right)^{2/3}$ shows that the most effective fusion energy scales with temperature to the two-thirds power.

3. Which of the following correctly contrasts nuclear fission and fusion regarding their raw fuel availability and waste products?

Explanation: Fission relies on limited uranium reserves and yields long-lived actinides, whereas fusion utilizes light isotopes (deuterium obtainable from water) and yields non-toxic helium-4 as its primary ash.

4. In the context of quantum tunneling across the Coulomb barrier, what does a higher reduced mass $\mu$ of the reactant pair imply for the Gamow exponent $G$?

Explanation: The Gamow exponent $G$ is proportional to $\mu^{1/2}$. A higher reduced mass increases $G$, which exponentially decreases the transmission coefficient and tunneling probability.

5. What is the primary reason why gravitational confinement works so effectively in stars compared to terrestrial reactors?

Explanation: Stellar gravitational fields create tremendous inward pressure, allowing massive particle densities and extremely long confinement times, easily satisfying the Lawson criterion on a macro scale.

6. If two deuterons fuse via the channel $^{2}\text{H} + ^{2}\text{H} arrow {}^{3}\text{He} + n$, what is the approximate Q-value?

Explanation: The deuterium-deuterium (D-D) fusion branch producing $^{3}\text{He}$ and a neutron has a Q-value of approximately $3.27\text{ MeV}$.

7. What happens to the Coulomb potential barrier $V_c$ if the separation distance $r$ between two protons is halved?

Explanation: Since electrostatic potential energy is inversely proportional to separation distance ($V_c \propto 1/r$), halving $r$ doubles the Coulomb potential barrier height.

8. Why is high plasma density alone insufficient for achieving fusion ignition without adequate confinement time?

Explanation: The Lawson criterion requires the product of density and time ($n \tau_E$). If confinement time is too short, heat escapes faster than $\alpha$ particle collisions can replenish it, causing the plasma to quench.

9. In stellar nucleosynthesis, what reaction sequence bridges the mass gap at $A = 5$ and $A = 8$ where no stable nuclei exist?

Explanation: Because there are no stable nuclides with mass numbers 5 or 8, standard proton addition fails. Stars overcome this via the triple-$\alpha$ process, fusing three $^{4}\text{He}$ nuclei into $^{12}\text{C}$.

10. Which UP TGT/PGT core concept best explains why stellar cores do not instantly explode like a nuclear bomb despite continuous fusion?

Explanation: Stars maintain a stable steady state through hydrostatic equilibrium: any temperature spike increases pressure and expands the core, cooling it down; any contraction heats it up, regulating the fusion rate.