Mathematics • Class 6 Appendix-II Item 5 150 Mins Overall

Ratio and Proportion

Pointwise AISSEE Class 6 Mathematics guide for Ratio and Proportion (Topic 5). Learn ratio definitions, unit standardization, dividing quantities, product of extremes equals product of means, and mean proportional calculations.

Overview & Fundamental Concept

Pointwise AISSEE Class 6 Mathematics guide for Ratio and Proportion (Topic 5). Learn ratio definitions, unit standardization, dividing quantities, product of extremes equals product of means, and mean proportional calculations.

Official Syllabus Coverage Breakdown
Syllabus Item Prescribed Scope Exam Relevance & Pedagogical Objective
Item 5 Meaning of ratio, comparison of quantities of the same kind, proportion as equality of two ratios, extremes and means, finding missing terms. Master ratio reduction, unit harmonization, dividing totals into ratio parts, proportion extremes-means equivalence, and mean proportionals for AISSEE Class VI.
1. The Concept of Ratio & Unit Harmonization
  • Definition of Ratio: A ratio is a mathematical comparison of the sizes of two quantities of the same kind and expressed in the same unit by the process of division.
  • Notation & Terminology: The ratio of quantity $a$ to quantity $b$ is written as $a : b$ (read as '$a$ is to $b$') or as the fraction $\frac{a}{b}$. The first term $a$ is called the Antecedent, and the second term $b$ is called the Consequent ($b \ne 0$).
  • Ratio has NO Units: Because a ratio is a comparison of two quantities in identical units, the units cancel out completely. A ratio is a pure abstract number.
  • Order Matters: The ratio $a : b$ is NOT the same as $b : a$ (unless $a = b$). For instance, if boys to girls is $3 : 2$, girls to boys is $2 : 3$.
  • Unit Harmonization Requirement: Two quantities can only be compared when converted into identical units. For example, comparing $40\text{ cm}$ to $2\text{ m}$: first convert $2\text{ m} = 200\text{ cm}$, giving ratio $40 : 200 = 1 : 5$ (never $40 : 2$).
Quantities to CompareRaw ComparisonHarmonized UnitsSimplest Ratio
50 paise to ₹250 paise : ₹250 paise : 200 paise1 : 4
25 cm to 1.5 m25 cm : 1.5 m25 cm : 150 cm1 : 6
500 g to 2 kg500 g : 2 kg500 g : 2000 g1 : 4
45 minutes to 2 hours45 min : 2 hrs45 min : 120 min3 : 8
8 months to 2 years8 months : 2 years8 months : 24 months1 : 3
AISSEE Trap Alert • The Different Units Trap

AISSEE examiner favorite: 'Find the ratio of 30 paise to ₹3'. Unprepared candidates write 30:3 = 10:1. The correct answer is 30 paise : 300 paise = 1 : 10! ALWAYS equalize units first.

2. Dividing a Quantity in a Given Ratio
  • Part-to-Whole Ratio Logic: If an amount $Q$ is to be shared between two persons in the ratio $a : b$:
  • • Sum of Ratio Terms: Total equal parts $= a + b$.
  • • First Person's Share: $\frac{a}{a + b} \times Q$.
  • • Second Person's Share: $\frac{b}{a + b} \times Q$.
  • Three-Part Extended Ratios: When dividing among three entities in ratio $a : b : c$, total parts $= a + b + c$. Each share is $\frac{\text{term}}{\text{sum of terms}} \times Q$.
Exam Trick • One-Part Value Method
Find the value of 1 ratio part first: $\text{Value of 1 part} = \frac{\text{Total Amount}}{\text{Sum of Ratio Terms}}$. Then multiply by each ratio term to get each individual share instantly!
3. Proportions, Extremes-Means Law & Mean Proportional
  • Definition of Proportion: An equality of two ratios is called a proportion. If two ratios $a : b$ and $c : d$ are equal, the four numbers $a, b, c, d$ are in proportion, written as: $$a : b :: c : d \quad \text{or} \quad \frac{a}{b} = \frac{c}{d}$$
  • Extremes and Means: In the proportion $a : b :: c : d$, the first and fourth terms ($a$ and $d$) are called Extremes (outer terms). The second and third terms ($b$ and $c$) are called Means (middle terms).
  • The Fundamental Law of Proportion: $$\text{Product of Extremes} = \text{Product of Means} \iff a \times d = b \times c$$
  • Finding Missing Term: If any one of the four terms is unknown, use the cross-multiplication identity: $x = \frac{b \times c}{d}$ or $x = \frac{a \times d}{b}$.
  • Continued Proportion & Mean Proportional: Three numbers $a, b, c$ are said to be in continued proportion if: $$\frac{a}{b} = \frac{b}{c} \iff b^2 = a \times c \implies b = \sqrt{a \times c}$$ Here, $b$ is called the Mean Proportional between $a$ and $c$, and $c$ is called the Third Proportional.
Proportion TermFormulaCalculation Example
Fourth Proportional to a, b, c$x = \frac{b \times c}{a}$Fourth proportional to 4, 9, 12: $(9 \times 12) / 4 = 27$
Third Proportional to a, b$x = \frac{b^2}{a}$Third proportional to 9, 12: $12^2 / 9 = 144 / 9 = 16$
Mean Proportional between a, c$b = \sqrt{a \times c}$Mean proportional of 4 and 16: $\sqrt{4 \times 16} = \sqrt{64} = 8$
Cadet Mnemonic • P-E-M Memory Key

Remember proportion equality:

  • Product of Extremes ($a \times d$)
  • Equals
  • Product of Means ($b \times c$)
Visual Concept Blueprint • Vector Architecture
EXTREMES & MEANS THEOREM: If a : b = c : d, then a × d = b × c a : b :: c : d Product of Extremes (a × d) Product of Means (b × c)

Speed Shortcuts & Mental Calculation Strategies

Master these high-yield time-saving heuristics curated by top AISSEE scorers to eliminate calculation bottlenecks and answer questions in under 45 seconds.

Shortcut Technique 1: Connecting Two Separate Ratios

To combine $A : B = a : b$ and $B : C = c : d$, equalize $B$'s term by multiplying: $A : B : C = (a \times c) : (b \times c) : (b \times d)$.

Shortcut Technique 2: Fractional Ratio Simplification

To simplify ratios of fractions like $\frac{1}{2} : \frac{1}{3} : \frac{1}{4}$, multiply each term by the LCM of denominators (LCM of 2, 3, 4 is 12) $\to 6 : 4 : 3$.

Shortcut Technique 3: Inverse Ratio Formulation

The inverse ratio of $a : b$ is $\frac{1}{a} : \frac{1}{b} = b : a$. For three terms $a : b : c$, the inverse ratio is $\frac{1}{a} : \frac{1}{b} : \frac{1}{c}$.

Interactive 3D Revision Flashcards Deck

Click any card to flip and reveal the key exam rule or topper secret.

REVISION FLASHCARD
What is the core rule & definition for Ratio and Proportion?
CADET MEMORY KEY
Cross-Product Rule: a : b :: c : d \implies a \times d = b \times c
REVISION FLASHCARD
Cadet Shortcut: How to solve Ratio and Proportion in under 30 seconds?
CADET MEMORY KEY
Fast MCQ Elimination: Check the last digit (unit digit) and estimate the order of magnitude to eliminate 2 distractors in under 10 seconds.
REVISION FLASHCARD
Exam Trap Alert: What pitfall do most candidates fall into?
CADET MEMORY KEY
Unitless Nature: A ratio has no units. Both terms must be converted to the same unit before forming ratio.
REVISION FLASHCARD
Rapid Memory Anchor for AISSEE Hall Recall:
CADET MEMORY KEY
Simplest Ratio: Always reduce ratio terms by dividing by their common factor.
REVISION FLASHCARD
What is the mean proportional between 9 and 25?
CADET MEMORY KEY
Formula: b = √(a × c) = √(9 × 25) = √(225) = 15.
Common Traps & Examination Pitfalls

Avoid the Speed-Guess Trap: Under AISSEE pressure, candidates frequently misread units (e.g., mixing metres and centimetres, or per hour and per second) and confuse complementary ($90^\circ$) with supplementary ($180^\circ$) angles. Read every stem carefully and check units before selecting your OMR option.

Key Identities & Formulas

Extremes-Means Identity
$$a \times d = b \times c$$
Product of extremes equals product of means in a:b::c:d.
Mean Proportional
$$b = \sqrt{a \times c}$$
Mean proportional b between terms a and c.
Third Proportional
$$c = \frac{b^2}{a}$$
Third proportional c when a, b, c are in continued proportion.
Step-by-Step Solved Examination Models
Solved Example 1 Model Problem
Divide ₹1,200 between Amit and Sumit in the ratio 3 : 5. How much does Sumit receive?
(A) ₹450
(B) ₹750
(C) ₹600
(D) ₹800
Detailed Solution: Total ratio parts = 3 + 5 = 8. Sumit's share = (5 / 8) × 1,200 = 5 × 150 = ₹750. (Amit receives ₹450).
Solved Example 2 Model Problem
If 4 : 5 :: 16 : x, find the value of x.
(A) 18
(B) 20
(C) 24
(D) 25
Detailed Solution: Product of extremes = Product of means. 4 × x = 5 × 16 => 4x = 80 => x = 80 / 4 = 20.
Solved Example 3 Model Problem
If $A : B = 2 : 3$ and $B : C = 4 : 5$, find the combined compound ratio $A : B : C$.
(A) 8 : 12 : 15
(B) 6 : 12 : 15
(C) 8 : 10 : 15
(D) 2 : 7 : 5
Detailed Solution: 1. We are given $A : B = 2 : 3$ and $B : C = 4 : 5$.
2. To connect them, make the common term $B$ identical in both ratios. The LCM of $3$ and $4$ is $12$.
3. Multiply first ratio by $4$: $A : B = (2 \times 4) : (3 \times 4) = 8 : 12$.
4. Multiply second ratio by $3$: $B : C = (4 \times 3) : (5 \times 3) = 12 : 15$.
5. Since $B$ is now $12$ in both, combine directly: $A : B : C = 8 : 12 : 15$. Correct Option is (A).

AISSEE High-Yield Practice Drills (10 Questions)

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Question 1 of 10 Exam Standard
Find the ratio of 40 paise to ₹2 in simplest form.
Correct Answer: Option (A)
Convert ₹2 to paise = 200 paise. Ratio = 40 : 200 = 40/40 : 200/40 = 1 : 5.
Question 2 of 10 Exam Standard
Find the ratio of 75 cm to 1.5 metres.
Correct Answer: Option (A)
1.5 m = 150 cm. Ratio = 75 : 150 = 1 : 2.
Question 3 of 10 Exam Standard
Are the numbers 12, 18, 20, 30 in proportion?
Correct Answer: Option (A)
Product of extremes = 12 × 30 = 360. Product of means = 18 × 20 = 360. Since both are equal, they are in proportion.
Question 4 of 10 Exam Standard
The ratio of boys to girls in a class of 45 students is 4 : 5. How many girls are there?
Correct Answer: Option (B)
Total parts = 4 + 5 = 9. Girls = (5 / 9) × 45 = 5 × 5 = 25 girls.
Question 5 of 10 Exam Standard
Find the mean proportional between 4 and 16.
Correct Answer: Option (B)
Mean proportional b = √(a × c) = √(4 × 16) = √64 = 8.
Question 6 of 10 Exam Standard
If a : b = 2 : 3 and b : c = 4 : 5, find a : c.
Correct Answer: Option (A)
a/c = (a/b) × (b/c) = (2/3) × (4/5) = 8/15 => a : c = 8 : 15.
Question 7 of 10 Exam Standard
Find the fourth proportional to 3, 7, and 15.
Correct Answer: Option (B)
3 : 7 :: 15 : x => 3 × x = 7 × 15 => 3x = 105 => x = 35.
Question 8 of 10 Exam Standard
The angles of a triangle are in the ratio 2 : 3 : 4. Find the largest angle.
Correct Answer: Option (C)
Sum of angles in triangle = 180°. Total parts = 2 + 3 + 4 = 9. Largest angle = (4 / 9) × 180° = 80°.
Question 9 of 10 Exam Standard
Two numbers are in the ratio 5 : 7. If their difference is 18, find the smaller number.
Correct Answer: Option (B)
Let numbers be 5x and 7x. 7x − 5x = 2x = 18 => x = 9. Smaller number = 5 × 9 = 45.
Question 10 of 10 Exam Standard
Which of the following ratios is the largest?
Correct Answer: Option (B)
3/4 = 0.75, 5/6 = 0.833, 7/9 = 0.777, 2/3 = 0.666. 5 : 6 is the largest.

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Last-Minute Cadet Revision Matrix

Rapid recall checkpoints to review 24 hours before stepping into the examination hall.

Concept Checkpoint High-Yield Exam Rule & Memory Anchor
Unitless Nature A ratio has NO units. Both quantities must be in the identical unit before computing.
Proportion Test To test if four numbers are in proportion, verify if Product of Extremes = Product of Means.
Mean Proportional Mean proportional between a and b is √(a × b).
Order Dependency The order of terms in a ratio is crucial: a:b is fundamentally different from b:a.
Frequently Asked Questions
How many questions from Ratio and Proportion appear in the AISSEE Class VI exam?
Typically, 2 to 3 questions directly test Ratio and Proportion in the 50-question Mathematics paper, contributing 6 to 9 marks towards the 150-mark section total.
Is there any negative marking for incorrect answers in AISSEE Class VI?
No. The National Testing Agency (NTA) does not apply negative marking in the AISSEE Class VI entrance examination. Candidates should attempt every single question.
What is the best way to revise Ratio and Proportion before the exam?
Review the high-yield formulas, practice the 10 interactive drill MCQs on this page, and memorize the revision checkpoints matrix.