Geometric progressions and visualisation · Explicit and recursive sequence rules · Linear patterns, growth, decay and modelling · 4 practice marks
Question 8
A culture has 80 cells initially and doubles each hour. Give explicit and recursive rules, find its population after 5 hours, and contrast its plotted points with linear growth.
Show step-wise answer
Nₙ = 80 × 2ⁿ, N₀ = 80, Nₙ₊₁ = 2Nₙ; N₅ = 2560.
- Each step multiplies by 2, so the values form a GP indexed from n = 0.
- The general rule is Nₙ = 80 × 2ⁿ and the recurrence is Nₙ₊₁ = 2Nₙ.
- After 5 hours the model gives 80 × 32 = 2560.
- Differences grow rather than staying constant. Its integer-time points are not collinear, unlike a linear model.
GP in fractals · Geometric progressions and visualisation · 4 practice marks
Question 9
A line segment of length 1 is replaced at each Koch-curve step by four segments, each one third as long. After n steps, find the segment count, individual length and total length. Evaluate at n = 2.
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4ⁿ segments of length 3⁻ⁿ; total length (4/3)ⁿ. At n = 2: 16 segments, each 1/9, total 16/9.
- Each stage multiplies the segment count by 4, starting with one segment.
- Each segment length is multiplied by 1/3, starting at length 1.
- Multiply count and length: 4ⁿ × 3⁻ⁿ = (4/3)ⁿ.
- Substitute n = 2. This illustrates GP scaling in a fractal construction.
Tower of Hanoi · Explicit and recursive sequence rules · 4 practice marks
Question 10
Explain the recursive Tower of Hanoi algorithm for n disks and derive its minimum-move formula. Calculate it for 5 disks.
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T₀ = 0; Tₙ = 2Tₙ₋₁ + 1 = 2ⁿ − 1; 31 moves for 5 disks.
- Move the top n − 1 disks to the spare peg using the same rules.
- Move the largest disk to the destination; then move the n − 1 disks onto it.
- This is necessary as well as sufficient: the largest disk can move only after the smaller disks are cleared, and they must be moved back. Thus Tₙ = 2Tₙ₋₁ + 1.
- Tₙ + 1 = 2(Tₙ₋₁ + 1); starting at T₀ + 1 = 1 gives Tₙ = 2ⁿ − 1. T₅ = 31.
Recursive and explicit Hanoi rules · 4 practice marks
Question 11
A learner proposes Tₙ = 2n − 1 as the minimum move count for n Hanoi disks. Use n = 3 to disprove it and obtain the correct recursive and explicit rules.
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The correct rules are T₀ = 0, Tₙ = 2Tₙ₋₁ + 1 and Tₙ = 2ⁿ − 1.
- For three disks the minimum is 7 moves, whereas 2n − 1 gives 5.
- Move the n − 1 smaller disks away, move the largest once, then transfer the smaller disks onto it.
- Thus Tₙ = 2Tₙ₋₁ + 1 with T₀ = 0.
- Adding 1 gives Tₙ + 1 = 2(Tₙ₋₁ + 1), so Tₙ + 1 = 2ⁿ and Tₙ = 2ⁿ − 1.