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Mechanics

Stokes' Theorem

Stokes' theorem relates the surface integral of the curl of a vector field over an open surface to the line integral of the vector field around the boundary curve of that surface. It serves as a higher-dimensional generalization of the Kelvin-Stokes theorem in vector calculus, fundamental for analyzing conservative fields and electromagnetic induction in mechanics and field theory.

UP TGT ScienceUP PGT PhysicsStudy Notes + Practice

Scope and prerequisites

TGT core

Evaluation of line integrals in 2D and 3D, verification of conservative force fields, and simple applications relating work done by a force vector to curl evaluation.

PGT extension

Rigorous vector proofs, applications to fluid circulation, relation between differential and integral forms of Maxwell's equations, and Stokes' theorem in curvilinear or generalized coordinate systems.

Prerequisites

  • Vector differentiation and cross product
  • Line integrals and surface integrals
  • Partial differentiation and Jacobians

Statement of Stokes' Theorem

  • Let S be a piecewise smooth oriented open surface bounded by a simple, closed, piecewise smooth boundary curve C.
  • If vector field F possesses continuous first-order partial derivatives in an open region containing S, then the line integral of F along C equals the surface integral of the curl of F over S.
  • The orientation of C must be consistent with the surface normal vector n via the right-hand rule.

Physical Interpretation of Curl

  • The curl of a vector field represents the infinitesimal circulation of the field at a point.
  • In mechanics, if F represents a velocity field of a fluid, the curl of F is proportional to the local vorticity or angular velocity vector of the fluid element.
  • A vector field is irrotational if and only if its curl is identically zero everywhere in the region.

Relation to Conservative Forces

  • A central force field such as the gravitational force or an electrostatic force is conservative, implying that curl(F) = 0.
  • By Stokes' theorem, the line integral (work done) around any closed path C in a conservative field is zero, as the enclosed surface integral of curl(F) vanishes.
  • Path independence of line integrals is directly connected to the vanishing of the curl through Stokes' theorem.

Orientation and Boundary Rules

  • The right-hand corkscrew rule defines the positive direction of the boundary curve C relative to the surface normal n.
  • If the fingers of the right hand curl in the direction of traversal along C, the thumb points in the direction of the unit normal vector n.
  • Reversing the orientation of the boundary curve C changes the sign of the resulting line integral.

Derivations

Proof for Infinitesimal Rectangular Element

Conditions: Applicable for a small rectangular surface element in the xy-plane bounded by dx and dy.

  • Consider a rectangular loop in the xy-plane with vertices (x,y), (x+dx,y), (x+dx,y+dy), and (x,y+dy).
  • Evaluate the line integral of $F = F_x i + F_y j around this closed loop$ by summing contributions along the four sides: int F.d$r = F_x(x$,y)dx + F_y(x+dx,y)dy - F_x(x,y+dy)dx - F_y(x,y)dy.
  • Rewrite the differences using partial derivatives: int F.d$r = [F_y(x+dx$,y) - F_y(x,y)]dy - [F_x(x,y+dy) - F_x(x,y)]d$x = (\frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y}) dx dy$.
  • Recognize the integrand as the z-component of the curl of F multiplied by the area element dA = dx dy.

Result: \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS

Reduction of Surface Independence

Conditions: For any two open surfaces S1 and S2 sharing the same oriented boundary curve C.

  • Let S1 and S2 form a closed surface V by joining them along their common boundary C with opposite orientations.
  • Apply the divergence theorem or combine Stokes' theorem applications to show that the flux of curl(F) through the closed surface is zero.
  • Conclude that the surface integral depends solely on the boundary curve C and not on the specific choice of the open surface S spanning C, provided the field is continuously differentiable.

Result: \iint_{S_1} (\nabla \times \mathbf{F}) \cdot d\mathbf{S} = \iint_{S_2} (\nabla \times \mathbf{F}) \cdot d\mathbf{S}

Formula sheet

Formula / lawEquationVariables and unitsConditions
Stokes' Theorem Integral Form$$\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$$F = Vector field, r = position vector, n = unit surface normal, S = open surface, C = boundary curve
Depends on field dimensions (e.g., Joules for force)
F is continuously differentiable on a surface S bounded by C
Curl in Cartesian Coordinates$$\nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ F_x & F_y & F_z \end{vmatrix}$$F_x, F_y, $F_z = Cartesian components of F$
Inverse meter times field units (m^-1 * [F])
Cartesian coordinate system
Work Done in Force Field$$W = \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$$W = Work done, F = Force vector
Joule (J)
Closed path C
Irrotational Field Condition$$\nabla \times \mathbf{F} = 0$$F = Conservative or irrotational vector field
m^-1 * [F]
Valid throughout simply connected domain
Differential Form of Faraday's Law (Maxwell-Faraday)$$\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t}$$E = Electric field, B = Magnetic flux density, t = time
V/m^2
Time-varying magnetic field
Stokes' Theorem for Position Vector Cross Field$$\oint_C (\mathbf{c} \times \mathbf{r}) \cdot d\mathbf{r} = 2 \mathbf{c} \cdot \mathbf{S}$$c = Constant vector, r = position vector, S = vector area
Variable
c is a constant vector
Scalar Potential Relation$$\mathbf{F} = -\nabla \phi \implies \nabla \times \mathbf{F} = 0$$phi = Scalar potential function
Scalar potential units
Conservative force field
Stokes' Theorem in Parametric Form$$\iint_S \left[ \left(\frac{\partial F_z}{\partial y} - \frac{\partial F_y}{\partial z}\right)\frac{\partial(y,z)}{\partial(u,v)} + \dots \right] du dv$$u, v = surface parameters
Field units times area
Smooth parametric surface representation

Graphs and experiments

Surface Bounded by a Closed Curve

Draw: A 3D open bowl-like or cap-like surface S bounded by a closed contour curve C with an arrow indicating counterclockwise positive orientation and an outward unit normal vector n.

Interpret: Illustrates the geometric relationship between the 2D boundary curve C and the 3D surface S required for setting up Stokes' theorem limits.

Exam use: Tested in conceptual questions regarding correct choice of orientation and surface bounding.

Stokes' Paddlewheel Experiment Analogy

Draw: A tiny paddle wheel placed in a swirling fluid velocity field v, where the axis of rotation aligns with the local curl vector (nabla cross v).

Interpret: Demonstrates that the curl measures the axis and magnitude of local rotational tendency (vorticity) in a vector field.

Exam use: Frequently referenced in qualitative PGT questions regarding physical meaning of curl.

Conservative Field Contour Map

Draw: Closed equipotential contours with a closed path C intersecting them, demonstrating zero net work done along C.

Interpret: Visualizes why the line integral of a conservative force over a closed loop vanishes due to zero curl.

Exam use: Used in numerical and theoretical TGT/PGT questions on conservative forces.

Solved numericals

TGT core

Evaluate the line integral of the vector field $F = y i + x j around the circle x^2 + y^2 = 1 in the xy-plane$, traversed in the counterclockwise direction.

  • Identify the vector field components: $F_x = y$ and $F_y = x$.
  • Compute the curl of F: \nabla \times \mathbf{F} = (\frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y}) \mathbf{k} = (1 - 1)\mathbf{k} = 0.
  • Apply Stokes' theorem: \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{k} \, d$S = \iint_S 0 \$, dS = 0.

Answer: 0

PGT extension

Verify Stokes' theorem for the vector field $F = -y^2 i + x j + z z k over the upper hemisphere x^2 + y^2 + z^2 = 4$, z >= 0, bounded by the circle x^2 + $y^2 = 4 in the xy-plane$.

  • Compute line integral: Parameterize the boundary circle C as x = 2 cos t, y = 2 sin t, z = 0 for t from 0 to 2\pi. Then d\mathbf{r} = (-2 \sin t \mathbf{i} + 2 \cos t \mathbf{j}) dt.
  • Evaluate \oint_C \mathbf{F} \cdot d\mathbf{r} = \int_0^{2\pi} [(-4 \sin^2 t)(-2 \sin t) + (2 \cos t)(2 \cos t)] d$t = \int_0^{2\pi} (8 \sin^3 t + 4 \cos^2 t) dt = 0 + 4(\pi) = 4\pi$.
  • Compute curl of F: \nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \partial_x & \partial_y & \partial_z \\ -y^2 & x & z \end{vmatrix} = (0)\mathbf{i} + (0)\mathbf{j} + (1 - (-2y))\mathbf{k} = (1 + 2y)\mathbf{k}.
  • Evaluate surface integral: \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, d$S = \iint_S (1 + 2y) \frac{z}{2} \$, dS_{xy} over the disk x^2 + y^2 <= 4. Using polar coordinates, symmetry eliminates the 2y term, leaving \int_0^{2\pi}\int_0^2 1 \cdot r \, dr \, d$\theta = \pi (2^2) = 4\pi$.
  • Both integrals yield 4\pi, thus verifying Stokes' theorem.

Answer: 4\pi

PGT extension

Using Stokes' theorem, evaluate \oint_C (y \mathbf{i} + z \mathbf{j} + x \mathbf{k}) \cdot d\mathbf{r} where C is the triangle with vertices (1,0,0), (0,1,0), and (0,0,1) oriented counterclockwise as viewed from the origin.

  • Identify $F = y i + z j + x k$.
  • Calculate \nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \partial_x & \partial_y & \partial_z \\ y & z & x \end{vmatrix} = -\mathbf{i} - \mathbf{j} - \mathbf{k}.
  • The plane of the triangle is x + y + z = 1. The unit normal vector pointing upward is \mathbf{n} = \frac{\mathbf{i} + \mathbf{j} + \mathbf{k}}{\sqrt{3}}.
  • Compute the dot product: (-\mathbf{i} - \mathbf{j} - \mathbf{k}) \cdot \frac{\mathbf{i} + \mathbf{j} + \mathbf{k}}{\sqrt{3}} = -\frac{3}{\sqrt{3}} = -\sqrt{3}.
  • Calculate the area of the triangular surface S. The vertices give side vectors, yielding an area of \frac{\sqrt{3}}{2}.
  • Evaluate surface integral: \iint_S (-\sqrt{3}) \, d$S = -\sqrt{3} \times \frac{\sqrt{3}}{2} = -\frac{3}{2}$.

Answer: -1.5

Assumptions and limitations

  • The surface S must be orientable, meaning a consistent unit normal vector can be defined continuously across the entire surface.
  • The vector field F and its first-order partial derivatives must be continuous throughout an open region containing the surface S and its boundary C.
  • The theorem is restricted to 3D Euclidean space; higher-dimensional analogues require the generalized Stokes' theorem on differential forms.

Common misconceptions

Common error: Assuming Stokes' theorem applies only to flat surfaces in the xy-plane.

Correct: Stokes' theorem applies to any piecewise smooth open orientable surface in 3D space bounded by curve C.

The surface can be curved, warped, or folded as long as it has a well-defined boundary curve and continuous normal.

Common error: Thinking the choice of surface S alters the value of the surface integral for a given boundary C.

Correct: Any two surfaces sharing the same oriented boundary curve yield the exact same value for the surface integral of the curl.

Because the line integral depends solely on the boundary curve C, any surface spanning C gives identical results.

Common error: Ignoring the relative orientation between the curve C and surface normal n.

Correct: Reversing the traversal direction of C flips the sign of the line integral.

Orientation consistency via the right-hand rule is mandatory for the equality in Stokes' theorem to hold.

Quick revision

  • Stokes' theorem connects the line integral around a closed boundary to the surface integral of the curl over the enclosed area: \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS.
  • Stokes' Theorem Integral Form: \oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS
  • Curl in Cartesian Coordinates: \nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\ F_x & F_y & F_z \end{vmatrix}

Must remember

  • Stokes' theorem relates a surface integral of the curl of a vector field over an open surface $S$ to the line integral of the vector field around its boundary curve $C$: $\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$.
  • The orientation of the boundary curve $C$ and the surface unit normal vector $\mathbf{n}$ must be consistent according to the right-hand rule.
  • A vector field is irrotational if and only if its curl vanishes everywhere: $\nabla \times \mathbf{F} = 0$.
  • Conservative forces (such as electrostatic and gravitational forces) possess zero curl, making work done around any closed loop zero and the line integral path-independent.
  • The value of the surface integral depends solely on the boundary curve $C$ and is invariant under the choice of the spanning open surface $S$.

Glossary

Stokes' TheoremA fundamental theorem in vector calculus converting a surface integral of a curl over an open surface into a line integral around its boundary.
CurlA differential operator representing the infinitesimal circulation or local rotation rate of a vector field at a point, denoted as $\nabla \times \mathbf{F}$.
Irrotational FieldA vector field whose curl is identically zero throughout its domain, equivalent to being conservative.
Right-Hand RuleA convention relating the positive direction of traversal along a boundary curve $C$ to the direction of the surface normal $\mathbf{n}$.

Comparison of Vector Integral Theorems

TheoremIntegral RelationDomain Dimension
Green's Theorem$\oint_C (P dx + Q dy) = \iint_D (\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y}) dA$2D plane region
Stokes' Theorem$\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$3D surface bounded by 3D curve
Divergence Theorem$\iint_S \mathbf{F} \cdot \mathbf{n} \, dS = \iiint_V (\nabla \cdot \mathbf{F}) dV$3D volume bounded by closed surface

Practice Quiz

Choose an option to reveal the explanation.

1. What does Stokes' theorem directly relate?

Explanation: Stokes' theorem states that the line integral of a vector field $\mathbf{F}$ around a closed boundary curve $C$ equals the surface integral of its curl over any spanning surface $S$.

2. For a conservative force field $\mathbf{F}$, what is the value of $\nabla \times \mathbf{F}$?

Explanation: Conservative forces satisfy $\nabla \times \mathbf{F} = 0$, meaning the field is irrotational.

3. If the orientation of the boundary curve $C$ is reversed, what happens to the sign of the line integral $\oint_C \mathbf{F} \cdot d\mathbf{r}$?

Explanation: Reversing the traversal direction of the boundary curve $C$ changes the sign of the line integral because the direction of the tangent vector $d\mathbf{r}$ is inverted.

4. Which rule connects the positive traversal direction of curve $C$ with the surface normal $\mathbf{n}$?

Explanation: The right-hand corkscrew rule (or right-hand rule) specifies that if fingers curl along $C$, the thumb points along $\mathbf{n}$.

5. What is the curl of a position vector $\mathbf{r} = x\mathbf{i} + y\mathbf{j} + z\mathbf{k}$?

Explanation: Evaluating $\nabla \times \mathbf{r}$ yields zero components for all partial derivatives, resulting in the zero vector.

6. Which of the following differential equations represents Maxwell-Faraday law using curl?

Explanation: The Maxwell-Faraday equation in differential form is $\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t}$, linking electric field curl to time-varying magnetic fields.

7. If two different open surfaces, $S_1$ and $S_2$, share the same oriented boundary curve $C$, what is the relationship between their surface integrals of $\nabla \times \mathbf{F}$?

Explanation: Since both surface integrals equal the identical line integral around $C$, the surface integrals over $S_1$ and $S_2$ must be equal.

8. What is the physical significance of the curl of a fluid velocity field?

Explanation: In fluid mechanics, the curl of a velocity field represents the local vorticity, which is twice the local angular velocity vector of the fluid element.

9. What is the work done by a conservative force field around any closed path $C$?

Explanation: By Stokes' theorem, $\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$. For conservative forces, $\nabla \times \mathbf{F} = 0$, so the work done is zero.

10. If $\mathbf{F} = -\nabla \phi$, what can be deduced about $\nabla \times \mathbf{F}$?

Explanation: The curl of any gradient of a scalar field is identically zero ($\nabla \times (\nabla \phi) = 0$).

11. Which coordinate system is most commonly used for evaluating the determinant formula for curl?

Explanation: The cross-product determinant with unit vectors $\mathbf{i}, \mathbf{j}, \mathbf{k}$ and partial derivatives is standard for Cartesian coordinates.

12. What is the unit of the curl of a force field $\mathbf{F}$ measured in Newtons?

Explanation: Curl involves spatial derivatives ($\partial / \partial x$), dividing the field unit by meters, giving N/m (or m$^{-1} \cdot [\mathbf{F}]$).

13. Which theorem is a special planar case of Stokes' theorem when the surface lies entirely in the $xy$-plane?

Explanation: Green's theorem is the 2D planar manifestation of Stokes' theorem.

14. Can Stokes' theorem be applied to a closed surface like a sphere?

Explanation: Stokes' theorem applies to open surfaces bounded by a curve $C$. A closed surface has a null boundary ($C = \emptyset$), making the boundary line integral zero.

15. What is the result of $\oint_C (\mathbf{c} \times \mathbf{r}) \cdot d\mathbf{r}$ where $\mathbf{c}$ is a constant vector and $\mathbf{r}$ is the position vector?

Explanation: By vector identity and Stokes' theorem, $\nabla \times (\mathbf{c} \times \mathbf{r}) = 2\mathbf{c}$, leading to $\iint_S 2\mathbf{c} \cdot \mathbf{n} \, dS = 2\mathbf{c} \cdot \mathbf{S}$.

PYQ Patterns

These are pattern-based practice questions. Authentic year labels are only used when verified from a source.

1. If $\mathbf{F} = y\mathbf{i} + z\mathbf{j} + x\mathbf{k}$, what is the curl of $\mathbf{F}$, i.e., $\nabla \times \mathbf{F}$?

Explanation: Using the determinant formula: $\nabla \times \mathbf{F} = \begin{vmatrix} \mathbf{i} & \mathbf{j} & \mathbf{k} \\ \partial_x & \partial_y & \partial_z \\ y & z & x \end{vmatrix} = \mathbf{i}(0 - 0) - \mathbf{j}(1 - 0) + \mathbf{k}(0 - 1) = -\mathbf{j} - \mathbf{k}$... Wait, let's re-evaluate: $\frac{\partial x}{\partial y} = 0$, $\frac{\partial z}{\partial z} = 1$ for $y-component$ -> $\frac{\partial F_z}{\partial y} - \frac{\partial F_y}{\partial z} = 0 - 0 = 0$. Let's check: $F_x=y, F_y=z, F_z=x$. $\nabla \times \mathbf{F} = (\partial_y F_z - \partial_z F_y)\mathbf{i} + (\partial_z F_x - \partial_x F_z)\mathbf{j} + (\partial_x F_y - \partial_y F_x)\mathbf{k} = (0 - 0)\mathbf{i} + (0 - 1)\mathbf{j} + (0 - 1)\mathbf{k} = -\mathbf{j} - \mathbf{k}$. Wait, option A says $-\mathbf{i} - \mathbf{j} - \mathbf{k}$. Let's recompute: $\partial_x F_y = 0, \partial_y F_x = 1 \implies 0 - 1 = -1$ for $\mathbf{k}$. $\partial_z F_x = 0, \partial_x F_z = 1 \implies 0 - 1 = -1$ for $\mathbf{j}$. $\partial_y F_z = 0, \partial_z F_y = 0 \implies 0$ for $\mathbf{i}$. So $-\mathbf{j} - \mathbf{k}$. Let's check options: Option A is $-\mathbf{i} - \mathbf{j} - \mathbf{k}$. Wait, if $F_x=y, F_y=z, F_z=x$, then $\nabla \times \mathbf{F} = -\mathbf{i} - \mathbf{j} - \mathbf{k}$? Let's check standard cyclic permutation: if $F=(y,z,x)$, curl is $(-1, -1, -1) = -\mathbf{i} - \mathbf{j} - \mathbf{k}$. Correct index 0.

2. Evaluate $\oint_C (x^2 y \mathbf{i} + y \mathbf{j}) \cdot d\mathbf{r}$ around the square region bounded by $x=0, x=1, y=0, y=1$ in the $xy$-plane using Stokes' theorem.

Explanation: Here $\mathbf{F} = x^2 y \mathbf{i} + y \mathbf{j}$. $\nabla \times \mathbf{F} = (0 - \frac{\partial}{\partial z}(...))\mathbf{k} + (0)\mathbf{i} + (0 - \frac{\partial}{\partial x}(x^2 y))\mathbf{k} = -x^2 \mathbf{k}$. Integrating over the square $0 \le x \le 1, 0 \le y \le 1$ with $\mathbf{n} = \mathbf{k}$ gives $\iint_S (-x^2) dx dy = - \int_0^1 x^2 dx \int_0^1 dy = -(\frac{1}{3})(1) = -\frac{1}{3}$... Wait, let's check: $\frac{\partial F_y}{\partial x} = 0$, $\frac{\partial F_x}{\partial y} = x^2$. So $(\nabla \times \mathbf{F}) \cdot \mathbf{k} = \frac{\partial F_y}{\partial x} - \frac{\partial F_x}{\partial y} = 0 - x^2 = -x^2$. Integral is $\int_0^1 \int_0^1 -x^2 dx dy = -1/3$. Let's adjust option D to $-1/3$ and set correct index to D (index 3). Let's fix options: ["$-1$", "$1/2$", "$0$", "$-\frac{1}{3}$"] and correct_index 3.

3. What is the physical condition for a vector field $\mathbf{F}$ to be derivable from a scalar potential $\phi$ throughout a simply connected domain?

Explanation: A vector field is conservative ($\mathbf{F} = -\nabla \phi$) if and only if its curl is identically zero ($\nabla \times \mathbf{F} = 0$).

4. For the vector field $\mathbf{F} = yz \mathbf{i} + zx \mathbf{j} + xy \mathbf{k}$, what is its curl?

Explanation: Calculate components: $\frac{\partial}{\partial y}(xy) - \frac{\partial}{\partial z}(zx) = x - x = 0$ for $\mathbf{i}$, and similarly for $\mathbf{j}$ and $\mathbf{k}$. Thus $\nabla \times \mathbf{F} = 0$.

5. In Stokes' theorem $\oint_C \mathbf{F} \cdot d\mathbf{r} = \iint_S (\nabla \times \mathbf{F}) \cdot \mathbf{n} \, dS$, if $\mathbf{F}$ has dimensions of Force and $C$ is a displacement path, what physical quantity does the line integral represent?

Explanation: The line integral of a force vector along a path $\mathbf{r}$ represents the work done $W = \oint \mathbf{F} \cdot d\mathbf{r}$.

6. Which of the following identities is identically zero for any continuously differentiable vector field $\mathbf{F}$?

Explanation: The divergence of the curl of any smooth vector field is always identically zero: $\nabla \cdot (\nabla \times \mathbf{F}) = 0$.

Timed Topic Test

Attempt these questions under a ten-minute limit using a separate timer.

1. State whether Stokes' theorem is valid if surface $S$ has a finite number of smooth pieces (piecewise smooth).

Explanation: Stokes' theorem holds for any piecewise smooth oriented open surface bounded by a simple, closed, piecewise smooth boundary curve.

2. If $\mathbf{F} = x^2 \mathbf{i} + y^2 \mathbf{j} + z^2 \mathbf{k}$, what is $\nabla \times \mathbf{F}$?

Explanation: All partial derivatives $\frac{\partial F_z}{\partial y}$, $\frac{\partial F_y}{\partial z}$, etc., equal zero because each component depends only on its own coordinate variable.

3. What is the primary condition required for a vector field to possess path independence for its line integrals?

Explanation: Path independence is equivalent to $\nabla \times \mathbf{F} = 0$ in a simply connected domain.

4. How does Maxwell-Faraday equation $\nabla \times \mathbf{E} = -\frac{\partial \mathbf{B}}{\partial t}$ relate to Stokes' theorem in integral form?

Explanation: Integrating $\nabla \times \mathbf{E}$ over surface $S$ and applying Stokes' theorem gives the electromotive force $\oint \mathbf{E} \cdot d\mathbf{r}$ equal to the negative rate of change of magnetic flux.

5. If a vector field $\mathbf{F}$ has a constant non-zero curl everywhere, what can be said about its line integral around a closed boundary enclosing area $A$ with normal aligned to the curl?

Explanation: By Stokes' theorem, $\oint_C \mathbf{F} \cdot d\mathbf{r} = (\nabla \times \mathbf{F}) \cdot \mathbf{n} A$, which scales linearly with area $A$.

6. Which of the following vector fields is NOT irrotational?

Explanation: For $\mathbf{F} = y\mathbf{i} - x\mathbf{j}$, $\nabla \times \mathbf{F} = (0 - 0)\mathbf{i} + (0 - 0)\mathbf{j} + (-1 - 1)\mathbf{k} = -2\mathbf{k} \neq 0$. Thus it is rotational.

7. In applying Stokes' theorem, what happens if the surface $S$ is chosen to be flat versus hemispherical, both sharing the same circular boundary $C$?

Explanation: Stokes' theorem guarantees that any surface bounded by $C$ yields the exact same surface integral because it equals the unique line integral around $C$.

8. What is the curl of the vector field $\mathbf{F} = xz^2 \mathbf{i} - xy \mathbf{j} + yz \mathbf{k}$ at point $(1, 1, 1)$?

Explanation: Let's check the correct option text and index: Option 2 gives $\mathbf{i} + 2\mathbf{j} - \mathbf{k}$. Let's set correct_index to 2.

9. Why is the condition that the boundary curve $C$ be 'simple' important in Stokes' theorem?

Explanation: A simple closed curve does not intersect itself, avoiding ambiguities in defining the orientation and spanning surface.

10. If $\mathbf{F} = (2x + y)\mathbf{i} + (3y - z)\mathbf{j} + (4z + x)\mathbf{k}$, what is $\nabla \times \mathbf{F}$?

Explanation: $\nabla \times \mathbf{F} = (\partial_y(4z+x) - \partial_z(3y-z))\mathbf{i} + (\partial_z(2x+y) - \partial_x(4z+x))\mathbf{j} + (\partial_x(3y-z) - \partial_y(2x+y))\mathbf{k} = (0 - (-1))\mathbf{i} + (0 - 1)\mathbf{j} + (0 - 1)\mathbf{k} = \mathbf{i} - \mathbf{j} - \mathbf{k}$. Wait, $\partial_y(4z+x) = 0$, $\partial_z(3y-z) = -1$. So $0 - (-1) = 1$ for $\mathbf{i}$. $\partial_z(2x+y) = 0$, $\partial_x(4z+x) = 1$. So $0 - 1 = -1$ for $\mathbf{j}$. $\partial_x(3y-z) = 0$, $\partial_y(2x+y) = 1$. So $0 - 1 = -1$ for $\mathbf{k}$. Thus $\mathbf{i} - \mathbf{j} - \mathbf{k}$. Let's adjust Option A to $\mathbf{i} - \mathbf{j} - \mathbf{k}$ and keep index 0.